Urban Art Association

Real Hackney Dave , by met on Apr 25, 2023 15:15:11 GMT 1,

Apr 24, 2023 11:07:07 GMT 1 Crime in the City said:

Apr 24, 2023 10:10:40 GMT 1 JD said:

Aug 18, 2022 7:53:22 GMT 1 JD said:

Real Hackney Dave Essex map framed by mr frameman .£500


delivered within M25 or pick up

JD

Balancing artworks on light switches is the best life hack I've seen this year... cheers! glwts!

Cleverly done. This almost seems like witchcraft.

But it's actually just down to physics, combined with the element of illusion.



ELUCIDATION


A.  View this setup as a lever mechanism:

(i)  the top-centre of the light switch acts as the tip of the fulcrum; and

(ii)  the framed artwork serves as the beam, and also as the two masses on either side of the fulcrum.



B.  Based on the frame's current placement on the light switch, determine where the tip of the fulcrum lies, distance-wise or proportionally, in relation to the entire length of the frame/beam.


Looks to me like it's at the frame length's 1/10 mark. In other words:

(i)  1/10 of the frame's length (distance 1, or D1) and weight (mass 1, or M1) is on the left side of the fulcrum; and

(ii)  9/10 of the frame's length (distance 2, or D2) and weight (mass 2, or M2) are on the right side of the fulcrum.



C.  For the purpose of this explanation, let's assume the entire frame would normally weigh 2 kg.

The side to the left of the fulcrum would then weigh 200g (M1, being 1/10 of 2 kg) and the right side would weigh 1.8 kg (M2, being 9/10 of 2 kg).



D.  However, it would be physically impossible for all of the weight measurements in point C above to be correct — because the lever (i.e. the framed artwork resting on the light switch) is currently balanced.


A balanced lever has the following relationship:

M1 x D1 = M2 x D2


Consider first the right side of the fulcrum: M2 (1.8 kg) x D2 (9) = 16.2

Given the lever is balanced, the left side of the fulcrum and equation must also be equal to 16.2.

And if we know for certain that D1 = 1, then M1 must somehow weigh 16.2 kg.

Now, 200g (1/10 of 2 kg) of M1 has already been accounted for. But not the mysterious, additional 16 kg.


So how can this possibly be?

It is hurting the brain; my rational mind is simultaneously expanding and collapsing.



E.  ANSWER

To allow a frame normally weighing 2 kg to balance in its current position on top of the light switch, JD must have secretly hidden around 16 kg of lead weights inside that frame at the bottom-left corner.


Mystery solved.

Yay to science, clear thinking and problem-solving skills.

Next, I'll explain why the moon landings could never have happened.

Apr 24, 2023 11:07:07 GMT 1 Crime in the City said:

Apr 24, 2023 10:10:40 GMT 1 JD said:

Aug 18, 2022 7:53:22 GMT 1 JD said:

Real Hackney Dave Essex map framed by mr frameman .£500


delivered within M25 or pick up

JD

Balancing artworks on light switches is the best life hack I've seen this year... cheers! glwts!

Cleverly done. This almost seems like witchcraft.

But it's actually just down to physics, combined with the element of illusion.



ELUCIDATION


A.  View this setup as a lever mechanism:

(i)  the top-centre of the light switch acts as the tip of the fulcrum; and

(ii)  the framed artwork serves as the beam, and also as the two masses on either side of the fulcrum.



B.  Based on the frame's current placement on the light switch, determine where the tip of the fulcrum lies, distance-wise or proportionally, in relation to the entire length of the frame/beam.


Looks to me like it's at the frame length's 1/10 mark. In other words:

(i)  1/10 of the frame's length (distance 1, or D1) and weight (mass 1, or M1) is on the left side of the fulcrum; and

(ii)  9/10 of the frame's length (distance 2, or D2) and weight (mass 2, or M2) are on the right side of the fulcrum.



C.  For the purpose of this explanation, let's assume the entire frame would normally weigh 2 kg.

The side to the left of the fulcrum would then weigh 200g (M1, being 1/10 of 2 kg) and the right side would weigh 1.8 kg (M2, being 9/10 of 2 kg).



D.  However, it would be physically impossible for all of the weight measurements in point C above to be correct — because the lever (i.e. the framed artwork resting on the light switch) is currently balanced.


A balanced lever has the following relationship:

M1 x D1 = M2 x D2


Consider first the right side of the fulcrum: M2 (1.8 kg) x D2 (9) = 16.2

Given the lever is balanced, the left side of the fulcrum and equation must also be equal to 16.2.

And if we know for certain that D1 = 1, then M1 must somehow weigh 16.2 kg.

Now, 200g (1/10 of 2 kg) of M1 has already been accounted for. But not the mysterious, additional 16 kg.


So how can this possibly be?

It is hurting the brain; my rational mind is simultaneously expanding and collapsing.



E.  ANSWER

To allow a frame normally weighing 2 kg to balance in its current position on top of the light switch, JD must have secretly hidden around 16 kg of lead weights inside that frame at the bottom-left corner.


Mystery solved.

Yay to science, clear thinking and problem-solving skills.

Next, I'll explain why the moon landings could never have happened.